Since the segments FE and GH are parallel, the angles [tex]\text{FHG}=22\degree[/tex]Also, the angle [tex]\begin{gathered} \text{FHG}=\frac{HG}{2} \\ \text{FHG}=\frac{180}{2} \\ \text{FHG}=90\degree \end{gathered}[/tex]Then, using the sum of internal angles in triangle FGH, we have:
[tex]\begin{gathered} 90+22+y=180 \\ y=180-90-22 \\ y=68\degree \end{gathered}[/tex]
