Given
Solution
[tex]\begin{gathered} SINCE\text{ is similar pentagon} \\ AB\text{ is similar to PQ} \\ AE\text{ is similar to PT} \\ \frac{AB}{AE}=\frac{PQ}{PT} \\ \frac{2}{3}=\frac{x}{2.7} \\ \text{cross multiply} \\ 3x=2\times2.7 \\ 3x=5.4 \\ \text{divide both sides by 3} \\ \frac{3x}{3}=\frac{5.4}{3} \\ \\ x=1.8 \end{gathered}[/tex]
The final answer
[tex]x=1.8[/tex]
