Multiplying the liters of solution by the concentration we obtain the moles of solute:
[tex]n=6.4L\cdot0.64M=4.096\text{moles of solute}[/tex]Now, multiply these moles by the molar mass:
[tex]4.096\text{moles}\cdot\frac{11.83g}{\text{mol}}=48.46g[/tex]There are 48.46g needed.