Question

f(x) = (x-1.5)^2 find the vertex

Answer 1

The given function is

$f(x)=(x-1.5)^2$

It is important to know that the function is in vertex form

$f(x)=a(x-h)^2+k$

Where h and k are the coordinates of the vertex.

Having said that, we can deduct that the vertex of the given function is (1.5, 0) because those are the values for h and k.

Hence, the answer is V(1.5, 0).