Question

Given f(x) = 4x -x^2 and domain of f is {-1,-2,0} find the range

Answer 1

To determine the range for this domain we evaluate the function in each value of the domain:

$\begin{gathered} f(-1)=4(-1)-(-1)^2=-5 \\ f(-2)=4(-2)-(-2)^2=-12 \\ f(0)=4(0)-(0)^2=0 \end{gathered}$

Therefore the range of the function is the set {-12,-5,0}