Question

What is the answer to the problem for sin, sec, tan. I don’t really need a detailed explanation just the answer. Thank you.

Answer 1

Answer:

$\begin{gathered} \sin(\theta)=-0.35 \\ \\ sec(\theta)=-1.07 \\ \\ \tan(\theta)=0.38 \end{gathered}$

Step-by-step explanation:

Remember that for a given terminal point of an angle, we define those trigonometric functions as following:

$\begin{gathered} \sin(\theta)=\frac{y}{\sqrt{x^2+y^2}} \\ \\ sec(\theta)=\frac{\sqrt{x^2+y^2}}{x} \\ \\ \tan(\theta)=\frac{y}{x} \end{gathered}$

This way, we'll have that:

$\begin{gathered} \sin(\theta)=-0.35 \\ \\ sec(\theta)=-1.07 \\ \\ \tan(\theta)=0.38 \end{gathered}$