Question

If the numerator of a fraction is increased by 3, the fraction becomes 3/4. If the denominator is decreased by 7, the fraction becomes 1. Determine the original fraction.Which of the following equations represents "If the numerator of a fraction is increased by 3, the fraction becomes 3/4"?(Hint: cross products)4n + 12 = 3dO 3n + 9 = 404n + 3 = 3d

Answer 1

So we're going to represent the problem: "If the numerator of a fraction is increased by 3, the fraction becomes 3/4" in an equation.

Let "n" be the numerator and let "d" be the denominator.

Since the numerator is increased by 3, we could represent this as n+3.

The denominator "d", is not suffering any change in this statement.

So, we can write:

$\frac{n+3}{d}=\frac{3}{4}$

If we multiply by cross:

$\begin{gathered} 4(n+3)=3d \\ 4n+12=3d \end{gathered}$

So, the answer is the first one.