Question

Hi, can you help me answer this question please, thank you!

Answer 1

Given :

$\operatorname{mean}\text{ (}\mu)=55.8\text{ ; standard deviation (}\sigma)=7.8$

b)

$P(X>58.3)=P(Z>\frac{X-\mu}{\sigma})$$P(X>58.3)=P(Z>\frac{58.3-55.8}{7.8})$$P(X>58.3)=P(Z>0.3205)$$P(X>58.3)=1-P(Z\leq0.3205)$$P(X>58.3)=1-0.6255$$P(X>58.3)=0.3745$