Question

Which measure is closest to the area of the circle?

Answer 1

To determine the area of a circle

Using Pythagoras theorem

$\begin{gathered} Hyp^2=opp^2\text{ + adj}^2 \\ x^2=4^2+4^2 \\ x^2\text{ = 16 + 16} \\ x^2\text{ = 32} \\ x\text{ = 4}\sqrt[]{2} \end{gathered}$$\begin{gathered} \text{Diameter = 4}\sqrt[]{2} \\ \text{Area of a circle = }\pi r^2 \\ radius\text{ = }\frac{Diameter}{2}\text{ = }\frac{\text{4}\sqrt[]{2}}{2} \\ \text{radius = 2}\sqrt[]{2} \end{gathered}$$\begin{gathered} \text{Area of the circle = }\pi r^2 \\ \text{Area of the circle = }\frac{22}{7}\text{ x (2}\sqrt[]{2})^2 \\ \text{Area of the circle = }\frac{22\text{ x 8}}{7} \\ \text{Area of the circle = }\frac{22\text{ x }8}{7} \\ \text{Area of the circle = 2}5.136 \\ \text{Area of the circle = 25.1 square unit}^{}\text{ } \end{gathered}$

Hence the value of the closet area of the circle = 25.1 square unit