We are tasked to write an algebraic equation with distributive property and solve it using the two-column proof.
For an algebraic equation, I will use the equation
[tex]-3(x+1)+6x=15[/tex]Let's start solving this problem by applying the distributive property on the first term -3(x+1). We have
[tex]\begin{gathered} -3(x+1)=-3\cdot x+(-3)(1)=-3x-3 \\ \rightarrow\rightarrow-3x-3+6x=15 \end{gathered}[/tex]The next step is to add like terms. We add -3x and 6x on the left-hand side of the equation. We get
[tex]\begin{gathered} -3x-3+6x=15 \\ \rightarrow3x-3=15 \end{gathered}[/tex]This will be followed by the addition property of equality. We add +3 on both sides of the equation so the -3 on the left-hand side of the equation will cancel out. We have
[tex]\begin{gathered} 3x-3+3=15+3 \\ 3x=18 \end{gathered}[/tex]Finally, to solve the equation, we use the division property of equality. We divide both sides by 3. We get
[tex]\begin{gathered} \frac{3x}{3}=\frac{18}{3} \\ x=6 \end{gathered}[/tex]The steps are summarized as follows