For the following equation, find the equation of the transverse axis of the hyperbola: the quantity of x minus 1 squared over 9 all minus the quantity of y minus 5 squared over 25 equals 1 .

Solution
We have the following equation:
[tex]\frac{(x-1)^2}{9}-\frac{(y-5)^2}{25}=1[/tex]And the transverse axis is:
y=5