the dimensions of the box is,
height h = 4 in
length l = 4.4 in
width b = 5 in
so this box is cuboid, os the surface area of the cuboid is,
[tex]A=2(l\times b+b\times h+h\times l)[/tex][tex]A=2(4.4\times5+5\times4+4\times4.4)[/tex][tex]\begin{gathered} A=2(22+20+17.6) \\ A=2\times59.6 \\ A=119.2\text{ inch\textasciicircum{}2} \end{gathered}[/tex]so the surface area is 119.2 square inch
thus, the correct answer is option A