SOLUTION
Now, on a die of 6 faces, we have 3 even numbers which are 2, 4 and 6
Probability is calculated as
[tex]\frac{expected\text{ outcome}}{total\text{ outcome }}[/tex]So, number of even number is 3, total die faces is 6
Probability of getting an even number becomes
[tex]\frac{3}{6}[/tex]Also there is only 1 face with 1.
So probability of getting a 1 is
[tex]\frac{1}{6}[/tex]Now, probability of getting an even number or a 1, means we add both, we have
[tex]\begin{gathered} \frac{3}{6}+\frac{1}{6} \\ \frac{3+1}{6} \\ =\frac{4}{6} \\ =\frac{2}{3} \end{gathered}[/tex]hence the answer is 2/3, the last option nswe