Question

Calculate the amount of heat needed to increase the temperature of 200 grams of water at 10°C to 95°C.

Answer 1

the amount of heat need is 71060 Joules

Explanation

The equation for the amount of heat needed to increase the temperature of water is as follows:

$\begin{gathered} E=mC(T_2-T_1) \\ where \\ \\ \end{gathered}$

where E is the amount of heat

C is the specific heat capacity of water having a standard value of 4180 J/kg*K

T is the final ans initial temperature in kelvin

m is the mass

so

Step 1

given

$\begin{gathered} mass=m=200\text{ gr=0.2 kg} \\ T_1=10\text{ \degree C} \\ T_2=95\text{ \degree C} \\ C=4180\text{ J/kh*K} \end{gathered}$

a) convert the temperature into kelvin

$\begin{gathered} 10\text{ \degree C=\lparen10+273\rparen K=283 K} \\ 95\text{ \degree C=\lparen95+273 \rparen K=368 K} \end{gathered}$

now, replace in the formula

$\begin{gathered} E=mC(T_{2}-T_{1}) \\ E=0.2\text{ kg*4180L/kg*K*\lparen368K-283 k\rparen} \\ E=71060\text{ J} \end{gathered}$

therefore, the amount of heat need is 71060 Joules

I hope this helps you