Respuesta :
We will investigate the laws associated with algebraic manipulations of numbers.
There are a total of three Laws asscoiated with the algebraic operators as follows:
[tex]\text{Commutative, Associative,Distributive}[/tex]Commutative Law:
This law pertains to the order in which a addition " + " and multiplication " x " operators are applied on two numbers.
Lets say we have two numbers named ( a ) and ( b ). The commutative law representing additon would be:
[tex]a\text{ + b = b + a}[/tex]The multiplication operator would be:
[tex]a\text{ x b = b x a }[/tex]We see that exchange of numbers does not change the result of both addition and multiplication.
Associative Law:
This law pertains to the application of an addition " + " and multiplication " x " operators in groups. The grouping of numbers is represented by a parenthesis " ( ) ".
Lets say we have three numbers ( a , b and c ). We can have three possible combinations of grouping with each operator as follows:
Addition:
[tex]a\text{ + ( b + c ) = b + ( a + c ) = c + ( a + b ) }[/tex]Multiplication:
[tex]a\text{ x ( b x c ) = b x ( a x c ) = c x ( a x b )}[/tex]We see that each group of combination above for both addition and multiplication leads to the same result disregarding which pair is operated first!
Distributive Law:
This law pertains to an application of addition operator on two element group which is multiplied by a third number.
Using the same three numbers ( a,b, and c ) we have:
[tex]c\text{ x ( a + b ) = }c\text{ x a + c x b}[/tex]The above represents the solving of parenthesis by removing the round brackets " ( ) " and applying the multiplication operator with each element in the group.
Andy tries to solve an equation as follows:
[tex]\text{Step 1: 5 }\cdot\text{( 2x + 5 ) = 100}[/tex]To remove the parenthesis on the left hand side of the " = " sign we need to apply the distributive law.
The next step involves the application of distributive law as follows:
[tex]\begin{gathered} 5\cdot2x\text{ + 5}\cdot5\text{ = 100} \\ \text{Step 2: 10x + 25 = 100} \end{gathered}[/tex]Therefore, we see that Andy applied the distributive law incorrectly in step 2. Where he applied the multiplication operator with just the first element of the group i.e ( 2x ) and left out on the second one i.e ( 5 ).
We will continue forward with the next step after applying the distributive law correctly. We will try to isolate the term involving the variable ( x ) by subtracting 25 on both sides of the " = " sign as follows:
[tex]\begin{gathered} 10x\text{ + 25 - 25 = 100 - 25 } \\ \text{Step 3: 10x = 75} \end{gathered}[/tex]Then we will divide the entire equation by the multiple of the variable ( x ) as follows:
[tex]\begin{gathered} \frac{10x}{10}\text{ = }\frac{75}{10} \\ \\ \text{Step4: x = 7.5} \end{gathered}[/tex]Therefore, the correction statement to Andy's solution would be:
[tex]\begin{gathered} \text{Andy made an error with distributive property in step 2, and x = 7.5.} \\ \text{Option A }\ldots\text{ correct statement} \end{gathered}[/tex]
