D. Move the point at (6, 6) to (6,3). What are the sidelength and area of the error square for this point?

Answer:
Side length = 3
Area = 9
Explanation:
the side length of the square error for this point will be the distance between the point (6, 6) and point (6, 3).
So, the distance between 2 points (x1, y1) and (x2, y2) is equal to:
[tex]\text{distance}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2_{}}[/tex]So, the distance between (6, 6) and (6, 3) is:
[tex]\begin{gathered} \text{distance}=\sqrt[]{(6-6)^2+(6-3)^2} \\ \text{distance}=\sqrt[]{3^2} \\ \text{distance}=\sqrt[]{9} \\ \text{distance}=3 \end{gathered}[/tex]Therefore, the side length is 3
Then, the area of the error square is the square of the distance. So, the area of the square error is:
[tex]\text{Area}=3^2=9[/tex]