Question

The length of a rectangle is 5ft longer than twice the width. If the perimeter is 100ft, find the length and width of the rectangle.

Answer 1

First, lets draw our rectangle, knowing that the length is 5ft longer than twice the width. Calling X the width, we have:

The question said that the perimeter is 100ft, wich gives us the followed expression:

$x\text{ + x + (2x+5) + (2x+5) = 100 }\Rightarrow\text{ 6x + 10 = 100 }\Rightarrow\text{ 6x=100-10 }$

Continuing ours calculations:

$6x=90\text{ }\Rightarrow\text{ x=}\frac{90}{6}\text{ }\Rightarrow\text{ x=15}$

So, our width is 15 ft, wich means that our length 35 ft.