We must find the value of x that makes the following equation true:
[tex]-8(x+5)=-3x-7+x-3[/tex]Basically we must solve the equation for x. We can start by distributing the product in the left side and adding like terms in the right side:
[tex]\begin{gathered} -8(x+5)=-3x-7+x-3 \\ -8x+(-8)\cdot5=-3x+x-7-3 \\ -8x-40=-2x-10 \end{gathered}[/tex]Then we add 8x+10 to both sides of this equation:
[tex]\begin{gathered} -8x-40+8x+10=-2x-10+8x+10 \\ -30=6x \end{gathered}[/tex]And we divide both sides by 6:
[tex]\begin{gathered} -\frac{30}{6}=\frac{6x}{6} \\ x=-5 \end{gathered}[/tex]AnswerThen the answer is option B, x=-5.