Given the Quadratic Equation:
[tex]2x^2-1=3x+4[/tex]You can rewrite it in this form:
[tex]ax^2+bx+c=0[/tex]In order to do that, you need to subtract the terms on the right side of the equation from both sides:
[tex]2x^2-1-(3x)-(4)=3x+4-(3x)-(4)[/tex][tex]2x^2-3x-5=0[/tex]Notice that:
[tex]\begin{gathered} a=2 \\ b=-3 \\ c=-5 \end{gathered}[/tex]Knowing that the Quadratic Formula is:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]You can substitute values:
[tex]x=\frac{-(-3)\pm\sqrt{(-3)^2-4(2)(-5)}}{2(2)}[/tex]Hence, the answer is:
[tex]x=\frac{-(-3)\pm\sqrt{(-3)^2-4(2)(-5)}}{2(2)}[/tex]