a rhombus has all its sides equal, therefore
AD=AB
solve the equality
[tex]\begin{gathered} 4x-2=3x+1 \\ 4x-3x=1+2 \\ x=3 \end{gathered}[/tex]
the value of x is 3, to find the measure of a side I will replace x=3 on any equation
[tex]4(3)-2=10[/tex]
the measure of a side is 10
the perimeter is the sum of alla sides, 4 on this case, so
[tex]10+10+10+10=40[/tex]
the perimeter is 40 units
