Question

This is a practice question.Wilma solved and answered the logarithmic equation in terms of x.(Look at the pic above to see the logarithmic equation and how she solved it) Is she correct? If not, name her mistakes.

Answer 1

Given the logarithmic equation

$\log _{4^x}2^a=3$

We are asked to solve in terms of x

Explanation

$\begin{gathered} \log _{4^x}2^a=3 \\ \text{resolve the base} \\ \log _{2^{2x}}2^a=3 \\ \text{Therefore,} \\ \frac{1}{2x}\log _22^a=3 \\ \frac{a}{2x}\log _22=3 \\ \frac{a}{2x}=3 \\ a=6x \\ \end{gathered}$