Question

In preparation for a hiking trip, Joe places a bottle containing 1.6 kg of water in the freezer overnight. If the waterwas initially at 20°C, how much heat must be removed from the water in order for all of it to freeze?Enter your answer as a positive number.

Answer 1

Given:

Mass = 1.6 kg

Temperature = 20°C

Let's determine how much heat must be removed from the water in order for all of it to freeze.

Apply the formula:

$Q=m*C\Delta T$

The freezing point of water is 0°C

Where:

m is the mass = 1.6 kg

C is specific heat of water = 4200 J/kg°C

T is the temperature change

Thus, we have:

$\begin{gathered} Q=1.6*4200(0-20) \\ \\ Q=1.6*4200*(0-20) \\ \\ Q=134400\text{ J} \end{gathered}$

Therefore, the amount of heat lost is 134400 J.

ANSWER:

134400 J