Explanation:
First we have to find the equation of line p, which is perpendicular to y=1/4x - 3, therefore its slope is reciprocal and opposite to the given line:
[tex]y_p=-4x+b[/tex]To find the y-intercept b we have to use the point. Replace x = -8, y = 2 and solve for b:
[tex]\begin{gathered} 2=-4(-8)+b \\ 2=32+b \\ b=2-32 \\ b=-30 \end{gathered}[/tex]The equation of line p is:
[tex]y_p=-4x-30[/tex]Now, line m is a dialation of line p centered at the origin, so the slope doesn't change - this means that line m is parallel to line p - and the y-intercept is the product of the y-intercept of line p by the scale factor:
[tex]\begin{gathered} y_m=-4x-30\cdot\frac{2}{5} \\ y_m=-4x-12 \end{gathered}[/tex]Answer:
The equation of line m is y = -4x - 12