The amount deposited is
[tex]P=\text{ \$2,810}[/tex]The interest rate compounded continuously is given as
[tex]\begin{gathered} r=3\text{ \%} \\ r=\frac{3}{100}-0.03 \end{gathered}[/tex]The time in years will be
[tex]\begin{gathered} t=\frac{30}{12} \\ t=2.5\text{years} \end{gathered}[/tex]The formula for the amount for continuous compound interest is given below as
[tex]A=Pe^{rt}[/tex]By substituting the values, we will have
[tex]\begin{gathered} A=Pe^{rt} \\ A=2,820\times e^{(0.03\times2.5)} \\ A=3028.85 \end{gathered}[/tex]Hence,
The final answer = $3,028.85