Respuesta :

[tex]\begin{gathered} 5\frac{2}{11}-3\frac{2}{18}=\frac{(11\times5)+2}{11}-\frac{(18\times3)+2}{18}=\frac{57}{11}-\frac{56}{18}=\frac{57}{11}-\frac{28}{9} \\ \end{gathered}[/tex]

finding the LCM for 11 and 9 = 99, then the corresponding subtraction is made

[tex]\begin{gathered} \frac{57\times9}{11\times9}-\frac{28\times11}{9\times11} \\ \frac{513}{99}-\frac{308}{99} \\ \frac{205}{99} \end{gathered}[/tex]

the answer is

[tex]\frac{205}{99}or2\frac{7}{99}[/tex]

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