Solve triangle QRS with the given parts. q = 9.10, r = 18.2, Q = 30.0°

Given:
q = 9.10, r = 18.2, Q = 30 degrees
Required: Solve triangle QRS
Explanation:
By using the Sine rule,
[tex]\frac{\sin Q}{q}=\frac{\sin R}{r}=\frac{\sin S}{s}[/tex]Plug the given values.
[tex]\frac{\sin30\degree}{9.10}=\frac{\sin R}{18.2}=\frac{\sin S}{s}[/tex]Consider
[tex]\frac{\sin30\degree}{9.10}=\frac{\sin R}{18.2}[/tex]Solve for R.
[tex]\begin{gathered} \frac{0.5}{9.10}=\frac{\sin R}{18.2} \\ \sin R=\frac{0.5\times18.2}{9.10} \\ =1 \\ \implies R=90\degree \end{gathered}[/tex]Now, use the fact that the sum of the interiorn angles od a r