Answer:
a)
[tex]\begin{gathered} \text{Original coordinates}\rightarrow\text{ Final coordinates} \\ D(-3,8)\rightarrow D^{\prime}(8,-3) \\ E(2,5)\rightarrow E^{\prime}(5,2) \\ F(-4,-1)\rightarrow F^{\prime}(-1,-4) \end{gathered}[/tex]
b)
[tex](x,y)\rightarrow(y,x)[/tex]
Explanation:
a)
The coordinates of the image on the graph are;
[tex]\begin{gathered} \text{Original coordinates}\rightarrow\text{ Final coordinates} \\ D(-3,8)\rightarrow D^{\prime}(8,-3) \\ E(2,5)\rightarrow E^{\prime}(5,2) \\ F(-4,-1)\rightarrow F^{\prime}(-1,-4) \end{gathered}[/tex]
b)
From the solution in a above, we can derive the general rule of the reflection from triangle DEF to D'E'F';
From the solution in a above, the values of the coordinates of x and y were interchanged.
x to y and y to x to give the image.
So, we can write the general rule as;
[tex](x,y)\rightarrow(y,x)[/tex]