Respuesta :

Given the triangle ABC:

The coordinates of the triangle will be as follows:

[tex]\begin{gathered} A\colon(-2,3) \\ B\colon(-2,-1) \\ C\colon(2,-1) \end{gathered}[/tex]

we will dilate the triangle about the origin with a scale factor of 0.5

The rule of dilation will be:

[tex](x,y)\rightarrow r(x,y)=(rx,ry)[/tex]

The image of the triangle after dilation will be A'B'C'

The coordinates of the triangle A'B'C' will be as follows:

[tex]\begin{gathered} A^{\prime}=0.5\cdot(-2,3)=(-1-1.5) \\ B^{\prime}=0.5\cdot(-2,-1)=(-1,-0.5) \\ C^{\prime}=0.5\cdot(2,-1)=(1,-0.5) \end{gathered}[/tex]

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