Solution:
Consider the illustration of intersecting secant theorem below
Applying the theorem to the problem before us, we have
[tex]\begin{gathered} x^2=2\text{ x \lparen y+2\rparen and } \\ x^2=3\text{ x \lparen3+4\rparen} \\ \\ Thus \\ x^2=3\text{ x 7 =21} \\ x=\sqrt{21} \\ \\ x^2=2(y+2) \\ 21=2y+4 \\ 2y+4=21 \\ 2y=21-4 \\ 2y=17 \\ y=\frac{17}{2} \\ \end{gathered}[/tex]
In summary,
21 goes into the first box.
17/2 goes into the second box
