Question

8x^2+ 7x= -1Round your answer to the nearest hundredth.If there is more than one solution, separate them with commas.

Answer 1

The equation given

$8x^2+7x=-1$

We need to solve this quadratic equation. First, let's change it to general form:

$8x^2+7x+1=0$

We know,

$\begin{gathered} a=8 \\ b=7 \\ c=1 \end{gathered}$

We can use the quadratic formula to solve for the values of x. The formula is

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

The steps are shown below:

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-7\pm\sqrt[]{(7)^2-4(8)(1)}}{2(8)} \\ x=\frac{-7\pm\sqrt[]{49-32}}{16} \\ x=\frac{-7\pm\sqrt[]{17}}{16} \\ x=-\frac{7}{16}+\frac{\sqrt[]{17}}{16},-\frac{7}{16}-\frac{\sqrt[]{17}}{16} \end{gathered}$