Answer:
x = -8 and y = 4
(-8, 4)
Explanation:
Given the below equations;
[tex]\begin{gathered} -3x+3y=36 \\ -2x-y=12 \end{gathered}[/tex]Let's go ahead and solve simultaneously using the substitution method.
From the 2nd equation, we have that;
[tex]\begin{gathered} -y=2x+12 \\ y=-2x-12 \end{gathered}[/tex]Let's put y = -2x - 12 into the 1st equation and solve for x;
[tex]\begin{gathered} -3x+3(-2x-12)=36 \\ -3x-6x-36=36 \\ -9x=72 \\ x=-\frac{72}{9} \\ \therefore x=-8 \end{gathered}[/tex]Since x = -8, let's put this into y = -2x - 12 and find y;
[tex]\begin{gathered} y=-2(-8)-12 \\ y=16-12 \\ \therefore y=4 \end{gathered}[/tex]
