If WY+XZ = 28, what is the length of PZ in parallelogram WXYZ?

Given data:
The expression for the sum of diagonals is WY+XZ = 28.
The given length is WP=8.
In parallelogram diagonals always bisects each other.
[tex]\begin{gathered} WY=2(WP) \\ =2(8) \\ =16 \end{gathered}[/tex]Substitute 16 for WP in the given expression.
[tex]\begin{gathered} 16+XZ=28 \\ XZ=12 \\ 2(PZ)=12 \\ PZ=6 \end{gathered}[/tex]Thus, PZ length is 6 units.