line with a slope of 2 and a y interception of -3
Equation of the line:
[tex]\begin{gathered} y=mx+b \\ \\ m\colon\text{slope} \\ b\colon y\text{ interception} \\ \\ y=2x-3 \end{gathered}[/tex]
Use the equation of the line to find a point in the line:
Find the value of y when x= 4
[tex]\begin{gathered} y=2(4)-3 \\ y=8-3 \\ y=5 \end{gathered}[/tex]
point (4,5)
y-interception gives you the point (0,-3)
Using the points (0,-3) and (4,5) graph the linea: put the points in the plane and draw a line that passes through those points:
