Given the following question:
Six people share 40 pounds of gold evenly. Which means we have to divide 40 by 6.
[tex]\begin{gathered} 40\div6 \\ \frac{40}{1}\div\frac{6}{1} \\ \text{ Apply KCF} \\ \frac{40}{1}\times\frac{1}{6} \\ 40\times1=40 \\ 1\times6=6 \\ \frac{40}{6}\div2=\frac{20}{3} \\ \text{ Convert into mixed number:} \\ \frac{20}{3}=20\div3=6\frac{2}{3} \\ =6\frac{2}{3} \end{gathered}[/tex]Which means each person will get 6 2/3 of gold.
Now for the second part:
Subtract 1 2/3 from the result, which means we subtract 1 2/3 from the solution
[tex]\begin{gathered} 6\frac{2}{3}-1\frac{2}{3} \\ \text{ Since the denominator are the same we only need to subtract:} \\ 2-2=0 \\ 3-3=0 \\ 6-1=5 \\ =5 \end{gathered}[/tex]After subtracting 1 2/3 from the evenly split gold each person will get 5 pieces of gold.
