Question

Graph the linear equation -x+5y=5

Answer 1

Given the linear equation;

$-x+5y=5$

We'll begin by re-writing in the slope-intercept form as follows;

$\begin{gathered} \text{The equation in slope-intercept form is;} \\ y=mx+b \\ -x+5y=5 \\ \text{Add x to both sides} \\ 5y=x+5 \\ \text{Divide both sides by 5} \\ \frac{5y}{5}=\frac{x+5}{5} \\ y=\frac{x}{5}+\frac{5}{5} \\ y=\frac{x}{5}+1 \end{gathered}$

To graph the linear equation, we shall use the intercepts method. That is plot two points where x = 0 and y = 0.

$\begin{gathered} \text{When x}=0 \\ y=\frac{0}{5}+1 \\ y=1 \\ \text{Therefore we have;} \\ (0,1) \\ \text{Similarly, when y}=0 \\ 0=\frac{x}{5}+1 \\ \frac{x}{5}=-1 \\ \text{Cross multiply and we'll have;} \\ x=-5 \\ \text{Therefore, we have;} \\ (-5,0) \end{gathered}$

With these two points we now have the graph;