Let x be one of the sides of the pool. The other side then will be 2.5x.
Now the volume of the pool is given by:
[tex]V=lwh[/tex]plugging the values we know we have:
[tex]\begin{gathered} 1440=2.5x\cdot x\cdot4 \\ 10x^2=1440 \\ x^2=144 \\ x=\sqrt[]{144} \\ x=12 \end{gathered}[/tex]Therefore the smaller dimension is 12 ft and the larger dimension is 30.