Question

Charlene is wrapping the box below. How much wrapping paper will she need to wrap the box with no overlap? 12 in. 3 in. 10 in.a. 186 in b. 372 in c. 480 in d. 558 in

Answer 1

Step 1: Write out the formula

$\text{TSA = }2(lw+lh+hw)$$\begin{gathered} \text{where} \\ \text{TSA = the total surface area of the box} \\ l=\text{ the length of the box} \\ w=\text{ the width of the box} \\ h=\text{ the height of the box} \end{gathered}$

Step 2: Write out the given values and substitute them into the formula

$\begin{gathered} l=12in \\ w=3in \\ h=10in \end{gathered}$

Therefore,

$\text{TSA = 2(12}\times3+12\times10+10\times3)=2(36+120+30)=2\times186=372in^2$

The quantity of wrapping needed is the total surface area of the box.

Therefore, the quantity of wrapping needed is 372 square inches. Choice B