The graph of a function is a line that passes through the coordinates (2, 11) and (8, 14).Part AWhich shows how to find the rate of change for the function?A.[tex] \frac{8 - 2}{14 - 11} [/tex]B.[tex] \frac{14 - 11}{8 - 2} [/tex]C.[tex] \frac{14 - 8}{11 - 2} [/tex]D.[tex] \frac{11 - 2}{14 - 8} [/tex]Part BWhich is an equation in terms of x and y for this function?A.[tex]y = \frac{1}{2} x + 10[/tex]B.[tex]y = \frac{2}{3} x + 9[/tex]C.[tex]y = \frac{3}{2} x + 8[/tex]D.[tex]y = 2x + 7[/tex]

Respuesta :

The slope of a line is defined as rise/run. In other words, it is the change in the y-coordinate over the change in x-coordinate.

Now, for the points (2, 11) and (8, 14) the change in y-coordinate is

[tex]14-11[/tex]

and the change in the x-coordinate is

[tex]8-2[/tex]

Therefore, the slope is

[tex]\frac{14-11}{8-2}[/tex]

which is choice B.

Part B.

The equation of a line is of the form

[tex]y=mx+b[/tex]

where m is the slope and b is the y-intercept.

Now, the slope we found from part A is

[tex]m=\frac{14-11}{8-2}=\frac{3}{6}=\frac{1}{2}[/tex]

Therefore,

[tex]y=\frac{1}{2}x+b[/tex]

we now just need to find b.

We find the y-intercept b using the point (2. 11) and putting in y =11 and x = 2 in the above equation gives

[tex]11=\frac{1}{2}(2)+b[/tex][tex]11=1+b[/tex][tex]\therefore b=10[/tex]

Hence, the equation of the line is

[tex]y=\frac{1}{2}x+10[/tex]

which is choice A,

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