The slope of a line is defined as rise/run. In other words, it is the change in the y-coordinate over the change in x-coordinate.
Now, for the points (2, 11) and (8, 14) the change in y-coordinate is
[tex]14-11[/tex]and the change in the x-coordinate is
[tex]8-2[/tex]Therefore, the slope is
[tex]\frac{14-11}{8-2}[/tex]which is choice B.
Part B.
The equation of a line is of the form
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept.
Now, the slope we found from part A is
[tex]m=\frac{14-11}{8-2}=\frac{3}{6}=\frac{1}{2}[/tex]Therefore,
[tex]y=\frac{1}{2}x+b[/tex]we now just need to find b.
We find the y-intercept b using the point (2. 11) and putting in y =11 and x = 2 in the above equation gives
[tex]11=\frac{1}{2}(2)+b[/tex][tex]11=1+b[/tex][tex]\therefore b=10[/tex]Hence, the equation of the line is
[tex]y=\frac{1}{2}x+10[/tex]which is choice A,