Respuesta :

Let the initial amount be $1 and use the rule of the compounded interest

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

P = 1

r = 3.3% = 3.3/100 = 0.03

n = 365

t = 1

[tex]\begin{gathered} A=1(1+\frac{0.033}{365})^{365\times1} \\ A=1.033548998 \end{gathered}[/tex]

Now find the annual rate using the percent of the increasing rule

[tex]P=\frac{N-O}{N}\times100[/tex]

N is the new amount

O is the old amount

[tex]\begin{gathered} \text{Perc}\mathrm{}=\frac{1.033548998-1}{1}\times100 \\ \text{Perc}\mathrm{}=3.355 \end{gathered}[/tex]

The annual percent is 3.355%

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