Let the initial amount be $1 and use the rule of the compounded interest
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]P = 1
r = 3.3% = 3.3/100 = 0.03
n = 365
t = 1
[tex]\begin{gathered} A=1(1+\frac{0.033}{365})^{365\times1} \\ A=1.033548998 \end{gathered}[/tex]Now find the annual rate using the percent of the increasing rule
[tex]P=\frac{N-O}{N}\times100[/tex]N is the new amount
O is the old amount
[tex]\begin{gathered} \text{Perc}\mathrm{}=\frac{1.033548998-1}{1}\times100 \\ \text{Perc}\mathrm{}=3.355 \end{gathered}[/tex]The annual percent is 3.355%