In account A:
1.
Mr. Malone is putting $200 first, then he deposits $15 each month
Since y is the total amount of money after x months, then
[tex]y=15x+200\rightarrow(1)[/tex]In account B:
2.
Mr. Malone is putting $300 first, then he deposits $10 each month
Since y is the total amount of money after x months, then
[tex]y=10x+300\rightarrow(2)[/tex]3.
We will subtract equation (1) from equation (2) to eliminate y
[tex]\begin{gathered} y-y=(10x-20x)+(300-200) \\ 0=-10x+100 \end{gathered}[/tex]Add 10x to each side
[tex]\begin{gathered} 0+10x=-10x+10x+100 \\ 10x=100 \end{gathered}[/tex]Divide both sides by 10
[tex]\begin{gathered} \frac{10x}{10}=\frac{100}{10} \\ x=10 \end{gathered}[/tex]Substitute x by 10 in equation (1) OR (2) to find y
[tex]\begin{gathered} y=20(10)+200 \\ y=200+200 \\ y=400 \end{gathered}[/tex]The solution of the equations is x = 10, y = 400
4.
After 10 months the accounts will have the same balance
5.
The balance will be $400