Answer:
(4, 20) is correct because the dilation of T(2, 10) by a scale factor of 2 will give T'(4, 20).
Explanation:
The coordinates of triangle TUV are T(2, 10), U(6, 2), and V(2, 2), if we dilate by a scale factor of 2, we'll have the below coordinates;
[tex]\begin{gathered} T\mleft(2,10\mright)\rightarrow T^{\prime}(2\times2,10\times2)\rightarrow T^{\prime}(4,20) \\ U\mleft(6,2\mright)\rightarrow U^{\prime}(6\times2,2\times2)\rightarrow U^{\prime}(12,4) \\ V(2,2)\rightarrow V^{\prime}(2\times2,2\times2)\rightarrow V^{\prime}(4,4) \end{gathered}[/tex]
We can see from the above that the correct coordinate for T' is (4, 20).
