Question

A person runs up 37 stairs of height 0.24 m. The person weighs 701.31 N. Howmuch energy does it take for the person to reach the top of the stairs?

Answer 1

Given data:

* The weight of the person is 701.31 N.

* The height of the each stair is 0.24 m.

* The number of stairs given is 37.

Solution:

The energy required to reach the top of stairs is,

$U=\text{mgH}$

where mg is the weight of the person, and H is the total height of 37 stairs,

Substituting the known values,

$\begin{gathered} U=701.31\times(37\times0.24) \\ U=6227.63\text{ J} \\ U=6.23\times10^3\text{ J} \\ U=6.23\text{ kJ} \end{gathered}$

Thus, the energy required to reach the maximum height of the 37 stairs is 6.23 kJ.