Question

rewrite the equation of a circle given below in standard form x² + 2x + y² + 22y - 10 = 0

Answer 1

$x^2+2x+y^2+22y-10=0​$$\begin{gathered} x^2+2x+y^2+22y-10=0​ \\ (x^2+2x)+(y^2+22y)=10​ \\ (x^2+2x+2)+(y^2+22y+121)=10​+1+121 \\ (x^2+2x+1)+(y^2+22y+121)=132 \\ (x+1)^2+(y+11)^2=132 \end{gathered}$

Answer:

$(x+1)^2+(y+11)^2=132$