Respuesta :

Answer:

Explanation:

Given the point (3, -7)

Sketching this, we have:

Only cosine is positive in this quadrant, so we have:

[tex]\begin{gathered} \sin\theta=-\frac{7}{\sqrt{58}} \\ \\ \cos\theta=\frac{3}{\sqrt{58}} \\ \\ \tan\theta=-\frac{7}{3} \end{gathered}[/tex]

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