hello
to solve this question, we would first of all sketch the probelm to give us a better understanding of what we need to do
from the figure above, we can proceed and use trigonometric ratio to find the missing angle
[tex]\begin{gathered} \text{SOHCAHTOA} \\ \text{SOH}=\sin \theta=\frac{opposite}{hypothenus} \\ \text{CAH}=\cos \theta=\frac{adjacent}{hypothenus} \\ \text{TOA}=\tan \theta=\frac{opposite}{adjacent} \end{gathered}[/tex]
from the question, we have the values of adjacent and hypothenus and we can simply apply tangent to find the angle.
[tex]\begin{gathered} \tan \theta=\frac{\text{opposite}}{\text{adjacent}} \\ opposite=4 \\ adjacent=7.5 \\ \tan \theta=\frac{4}{7.5} \\ \tan \theta=0.53 \\ \text{take the tangent inverse of 0.53} \\ \theta=\tan ^{-1}0.53 \\ \theta=27.92\approx28^0 \end{gathered}[/tex]
