Answer:
Option A. arithmetic; 76
Explanation:
Given the sequence of numbers 13, 20, 27, 34...
According to the given sequence, we can see that;
common difference = 20 - 13 = 27 - 20 = 7
Since the sequence has a common difference, this makes an ARITHMETIC SEQUENCE
The nth term of an arithmetic sequence is expressed as:
[tex]T_n=a+(n-1)d[/tex]
a is the first term
n is the number of terms
d is the common difference
Since we need the 10th term, hence n = 10
[tex]\begin{gathered} T_{10}=13+(10-1)(7) \\ T_{10}=13+9(7) \\ T_{10}=13+63 \\ T_{10}=76 \end{gathered}[/tex]
This shows that the sequence is an arithmetic sequence and the 10th term is 76
