Solution:
The relative frequency is expressed as
[tex]\begin{gathered} relative\text{ frequency =}\frac{f}{n} \\ where \\ f\Rightarrow number\text{ }of\text{ }times\text{ }the\text{ }data\text{ }occurred\text{ }in\text{ }an\text{ }observation \\ n\Rightarrow totalfrequency \end{gathered}[/tex]
Given the table below:
The total frequency is
[tex]\begin{gathered} 2+0+3+5+20+42+30+18 \\ =120 \end{gathered}[/tex]
To evalute the relative frequncy, we have
By summing up the relative frequncy, we have
[tex]\begin{gathered} 0.0167+0+0.025+0.0417+0.167+0.35+0.25+0.15 \\ =1.0004 \\ \approx1 \end{gathered}[/tex]
Hence, we can conclude that the relative frequencies add up to 1
