Question

Solve for G.D=3/5(F+G)

Answer 1

The equation given is

$\begin{gathered} D=\frac{3}{5}(F+G) \\ \end{gathered}$

We multiply the "3/5" with both F and G following the distributive property,

$D=\frac{3}{5}F+\frac{3}{5}G$

Now we take the term with "G" to one side and solve with the rules of algebra. We isolate G:

$\begin{gathered} D-\frac{3}{5}F=\frac{3}{5}G \\ \frac{D-\frac{3}{5}F}{\frac{3}{5}}=\frac{\frac{3}{5}G}{\frac{3}{5}} \\ G=\frac{D-\frac{3}{5}F}{\frac{3}{5}} \end{gathered}$

We dividing by a fraction, we can multiply by its reciprocal. It doesn't change anything.

So, further simplifying, we have:

$\begin{gathered} G=\frac{5}{3}\times(D-\frac{3}{5}F) \\ G=\frac{5}{3}D-(\frac{5}{3})(\frac{3}{5}F) \\ G=\frac{5}{3}D-F \end{gathered}$Final Answer$G=\frac{5}{3}D-F$