Respuesta :

Given the equation:

[tex](10+y)^2-y^2=-3x+11[/tex]

Then, expanding and operating this equation leads to:

[tex]\begin{gathered} 10^2+2\cdot10\cdot y+y^2-y^2=-3x+11 \\ 100+20y=-3x+11 \end{gathered}[/tex]

There are no quadratic terms, so the equation is linear. Now, converting it to standard form:

[tex]20y+3x=-89[/tex]

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