Respuesta :

ANSWER :

The answer is A. y^4 - 12y^3 + 54y^2 - 108y + 81

EXPLANATION :

From the problem, we have the expression :

[tex](y-3)^4[/tex]

we can write it as :

[tex](y-3)^4=[(y-3)^2]^2[/tex]

Perform the first power to the 2nd using :

[tex](a^2\pm b^2)=a^2\pm2ab+b^2[/tex]

[tex][(y-3)^2]^2=(y^2-6y+9)^2[/tex]

Next is to perform the next square :

[tex](y^2-6y+9)^2=(y^2-6y+9)(y^2-6y+9)[/tex]

We can distribute each term of the first parenthesis to the second parenthesis as :

[tex](a+b+c)(a+b+c)=a(a+b+c)+b(a+b+c)+c(a+b+c)[/tex]

Then :

[tex]\begin{gathered} (y^2-6y+9)(y^2-6y+9) \\ =y^2(y^2-6y+9)-6y(y^2-6y+9)+9(y^2-6y+9) \\ \text{ Then simplify :} \\ =(y^4-6y^3+9y^2)-(6y^3-36y^2+54y)+(9y^2-54y+81) \\ \text{ Combine like terms :} \\ =y^4-6y^3-6y^3+9y^2+36y^2+9y^2-54y-54y+81 \\ =y^4-12y^3+54y^2-108y+81 \end{gathered}[/tex]

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